Answer:
Option D.
Step-by-step explanation:
Given information:
Amplitude = 2 centimeters
Period = 6 seconds
Position at t = 0 is 2.
In simple harmonic motion the displacement is defined as
[tex]d=A\cos (2\pi ft)[/tex] .... (1)
where, A is amplitude and f is frequency.
[tex]Frequency=\dfrac{1}{Period}[/tex]
[tex]Frequency=\dfrac{1}{6}[/tex]
Substitute A=2 and [tex]f=\frac{1}{6}[/tex] in equation (1).
[tex]d=(2)\cos (2\pi (\frac{1}{6})t)[/tex]
[tex]d=2\cos (\frac{\pi }{3}t)[/tex]
Therefore, the correct option is D.