Answer:
The maximum value of the feasible regions is P=500
Step-by-step explanation:
we know that
To find out the maximum value of the feasible regions, substitute the value of x and the value of y of each region in the objective function P and then compare the results
we have
[tex]P=120x+100y[/tex]
Region 1 (0,5)
For x=0, y=5
substitute
[tex]P=120(0)+100(5)=500[/tex]
Region 2 (0,4)
For x=0, y=4
substitute
[tex]P=120(0)+100(4)=400[/tex]
Region 3 (4,0)
For x=4, y=0
substitute
[tex]P=120(4)+100(0)=480[/tex]
Region 4 (3,0)
For x=3, y=0
substitute
[tex]P=120(3)+100(0)=360[/tex]
Compare
The maximum value of the feasible regions is P=500