What is the maximum value of the feasible regions if P = 120x + 100y
Region 1 (0 ,5)
Region 2 ( 0, 4)
Region 3 (4,0)
Region 4 (3,0)

Respuesta :

Answer:

The maximum value of the feasible regions is P=500

Step-by-step explanation:

we know that

To find out the maximum value of the feasible regions, substitute the value of x and the value of y of each region in the objective function P and then compare the results

we have

[tex]P=120x+100y[/tex]

Region 1 (0,5)

For x=0, y=5

substitute

[tex]P=120(0)+100(5)=500[/tex]

Region 2 (0,4)

For x=0, y=4

substitute

[tex]P=120(0)+100(4)=400[/tex]

Region 3 (4,0)

For x=4, y=0

substitute

[tex]P=120(4)+100(0)=480[/tex]

Region 4 (3,0)

For x=3, y=0

substitute

[tex]P=120(3)+100(0)=360[/tex]

Compare

The maximum value of the feasible regions is P=500

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