Answer:
d. [tex]X^{A}X^{a}[/tex] × [tex]X^{a}Y[/tex]
Explanation:
Since the disorder is a recessive one, the daughter will need to inherit two recessive alleles, each one from the two parents in order for the disorder to manifest.
A cross between [tex]X^{A}X^{a}[/tex] and [tex]X^{a}Y[/tex] will yield the following offspring;
[tex]X^{A}X^{a}[/tex] female, carrier of disorder
[tex]X^{a}X^{a}[/tex] female, affected with disorder
[tex]X^{a}Y[/tex] male, affected with disorder
[tex]X^{A}Y[/tex] male, unaffected
Hence, the only parental pair that can have a daughter with the recessive disorder is [tex]X^{A}X^{a}[/tex] × [tex]X^{a}Y[/tex]
The correct option is d.