Answer:
0.09 × 10²³ molecules of O₂
Explanation:
Given data:
Mass of mercury(II) oxide = 6.54 g
Molecules of oxygen produced = ?
Solution:
Chemical equation:
2HgO → 2Hg + O₂
Number of moles of HgO:
Number of moles = mass/ molar mass
Number of moles = 6.54 g / 216.6 g/mol
Number of moles = 0.03 mol
Now we will compare the moles of HgO with oxygen.
HgO : O₂
2 : 1
0.03 : 1/2×0.03 = 0.015 mol
Number of molecules of oxygen:
1 mole of O₂ = 6.022 × 10²³ molecules of O₂
0.015 mole of O₂ :
0.015 × 6.022 × 10²³ molecules of O₂
0.09 × 10²³ molecules of O₂
