Question

Arrange the bromine-containing compounds CaBr2, Br2, NBr3, CBr4 in order of increasing predicted boiling point.

Answer 1

Explanation:

In an ionic compound, there will be strong force of attraction between the combining atoms due to the opposite charges present on them.

For example, $CaBr_{2}$ is an ionic compound where calcium has a +2 charge and each bromine atom has a -1 charge.

Therefore, in order to break the bond we need to provide more heat. Hence, boiling point of calcium bromide will be the highest.

$NBr_{3}$ is a covalent compound and as nitrogen is more electronegative in nature and also has a lone pair of electron hence, there will be a net dipole moment.

$CBr_{4}$ is also a covalent compound. And, as bromine is more electronegative than carbon atom so, dipole moment is in the outwards direction. Hence, in $CBr_{4}$ there will be zero dipole moment.

Therefore, its boiling is less than the boiling point of $NBr_{3}$.

$Br_{2}$ is a covalent compound and there will be no dipole moment.

Thus, we can conclude that given bromine-containing compounds are placed in their increasing boiling point order as follows.

    $Br_{2}$ < $CBr_{4}$ < $NBr_{3}$ < $CaBr_{2}$

Answer 2

The substance of bromine-containing compounds can be arranged in order of increasing predicted boiling point.

as Br2 < CBr4< NBr3<CaBr2

What is boiling point?

The boiling point of a substance serves as the temperature at which the vapor pressure of a liquid equals the pressure surrounding the liquid .

Before a substance can reach boiling point,then the bond in it is a determinant, CaBr2 posses an ionic bond which means the boiling point will be high.

Compare to CBr4, NBr4 and Br2 which posses Covalent bond, however Br2 has no dipole moment.

Learn more about boiling point at;*,

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