Answer:
0.15 M
Explanation:
Number of mili moles of acetic acid = molarity×volume in mL = 3.0×0.50 =
1.5 milimoles = 1.5×10^{-3} moles
Concentration of the acetic acid = number of moles×1000/volume in mL
= 1.5×10^{-3}×1000/10 = 0.15 M
Explanation:
The given data is as follows.
[tex]M_{initial}[/tex] = 0.50 M, [tex]V_{1}[/tex] = 3.00 ml
[tex]V_{2}[/tex] = 7.00 ml,
Therefore, calculate the total volume as follows.
Total volume = [tex]V_{1} + V_{2}[/tex]
= 3.00 ml + 7.00 ml
= 10.0 ml
Now, calculate the no. of moles of acetic acid as follows.
No. of moles of acetic acid = molarity × volume in mL
= 3.0 × 0.50
= 1.5 mmoles
= [tex]1.5 \times 10^{-3}[/tex] moles
(As 1 mole = 0.001 mmol)
Therefore, calculate the concentration of acetic acid as follows.
Concentration of the acetic acid = [tex]\text{number of moles} \times \frac{1000}{\text{volume in mL}}[/tex]
= [tex]1.5 \times 10^{-3} \times \frac{1000}{10}[/tex]
= 0.15 M
Thus, we can conclude that the concentration of acetic acid in buffer solution is 0.15 M.
