Answer:
The volume neccesary to complete reaction is 3.79L
Explanation:
First step: Think the equation
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Afterwards, ballance it.
Relation in reactants is 1:2, so 2 mol of NaOH react to 1 mol of sulfuric.
Gotta find my mol of NaOH
Mass / Molar weight = Mol
72.8 g / 40 g/m = 1.82 mol NaOH
As the relation is 1:2, I have the half of sulfuric: 0.91 mol.
By a rule of three, will be
2 mol NaOH __ react __ 1 mol H2SO4
1.82 mol NaOH __react ___ (1.82 .1)/2
Finally we have to work with molarity, which means mol/L. So, the rule of three is:
0.240 mol H2SO4 __are in __ 1 L
0.91 mol H2SO4___ are in ___ (0.91 .1)/0.240 = 3.79L
