Answer:
The seed as a fraction of the speed of light is [tex]\frac{3}{5}c[/tex]
Solution:
As per the question:
Suppose, [tex]t_{i}[/tex] be the rate of an identical clock between two time intervals.
For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:
t = [tex]\frac{5}{4}t_{i}[/tex]
Now,
Using the relation of time dilation, from Einstein's relation:
[tex]t = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}[/tex]
[tex]\frac{5}{4}t_{i} = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}[/tex]
Squaring both sides:
[tex](\frac{5}{4})^{2} = (\frac{1}{\sqrt{1 - \frac{v^{2}}{c^{2}}}})^{2}[/tex]
[tex]\frac{25}{16} = \frac{1}{{1 - \frac{v^{2}}{c^{2}}}}[/tex]
[tex]1 - \frac{16}{25} = \frac{v^{2}}{c^{2}}[/tex]
[tex]\frac{v}{c} = \sqrt{\frac{9}{25}}[/tex]
[tex]\frac{v}{c} = \frac{3}{5}[/tex]
[tex]v = \frac{3}{5}c[/tex]