Answer:
The speed is 1.52 m.
Explanation:
Given that,
Displacement =0.270 m
Distance = 0.130 m
Suppose a 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m.
We need to calculate the angular velocity
Using formula of angular velocity
[tex]\omega=\sqrt{\dfrac{k}{m}}[/tex]
Put the value into the formula
[tex]\omega=\sqrt{\dfrac{13.3}{0.321}}[/tex]
[tex]\omega=6.43\ rad/s[/tex]
We need to calculate the velocity
Using formula of velocity
[tex]v=\omega\sqrt{A^2-x^2}[/tex]
Put the value into the formula
[tex]v=6.43\times\sqrt{0.270^2-0.130^2}[/tex]
[tex]v=1.52\ m/s[/tex]
Hence, The speed is 1.52 m.
