Question

Find the y intersept of

y=logbase (b)(a-k) based on the constants b and k ?

Answer 1

Answer:

$(0, log_{b}(-k)), k < 0$

Step-by-step explanation:

$y = \log_{b}(a - k)$

To find the y-intercept, set a = 0 and solve for y.

$y = \log_{b}(0 - k)\\y = \log_{b}(-k)$

This equation is undefined for k ≥ 0.

There is a y-intercept only if k < 0. Only then can the argument of the log function be positive.

The y-intercept is at

$\mathbf{(0, log_{b}(-k)), k < 0}$

For example, if b = 2 and k = -3, log₂(3) = 1.585

The intercept is at (0, 1.585).