Answer:
Molar mass of silane = 32.15 g/mol
Explanation:
Given:
Pressure = 2.35 atm
Temperature = 22 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (22 + 273.15) K = 295.15 K
Volume = 42.9 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
2.35 atm × 4.81 L = n × 0.0821 L.atm/K.mol × 295.15 K
⇒n = 0.4665 moles
Given, Mass = 15.0 g
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]0.4665\ mole= \frac{15.0\ g}{Molar\ mass}[/tex]
Molar mass of silane = 32.15 g/mol