Answer:
a. Sample mean is 0.95 and Sample standard deviation is ≈0.058
b. [tex]H_{0}[/tex]: μ=1 calorie and [tex]H_{a}[/tex]: μ<1 calori
c. The appropriate statistic to test this hypothesis is t-statistic.
d. The value of the test statistic is -2,586
e. The appropriate number of degrees of freedom for this test statistic is 8
f. In 95% confidence, the claim that, on average, their diet soda has less than one calorie is true.
Step-by-step explanation:
a.
Sample mean is 0.95 (0.90+ 0.95+1.00+ 1.05+ 0.85+1.00+ 0.95+0.95+0.90)÷9
Sample standard deviation is ≈0.058 (sum of square differences from the mean)
b.
μ denote the true mean calories of all diet sodas produced by ABC Company.
Then
[tex]H_{0}[/tex]: μ=1 calorie
[tex]H_{a}[/tex]: μ<1 calori
c.
The appropriate statistic to test this hypothesis is t-statistic.
d.
The value of the test statistic is
t=[tex]\frac{X-M}{\frac{s}{\sqrt{N} } }[/tex] where
t=[tex]\frac{0.95-1}{\frac{0.058}{\sqrt{9} } }[/tex] ≈ -2,586
e.
The appropriate number of degrees of freedom for this test statistic is 8
f.
in 95% confidence, the result is significant, since one tail t(critical) with 8 degrees of freedom is bigger than t(sample) i.e. -1.860 > -2,586
We reject the null hypothesis in favor of the alternative hypothesis. Therefore the claim that, on average, their diet soda has less than one calorie is true.