Question

Assume that the enthalpy of fusion of ice is 6020 J/mol and does not vary appreciably over the temperature range 270–290 K. If 1.40 mol of ice at 0°C is melted by heat supplied from surroundings at 284 K, what is the entropy change in the surroundings in J/K

Answer 1

Answer:

29.7 J/K

Explanation:

To solve this problem we can use the equation

• ΔS = Δq/T

Where ΔS is the entropy change, Δq is the heat change, and T is the temperature.

• Δq= ΔH*mol

We put the data given by the problem and solve for ΔS:

• ΔS = 6020J/mol * 1.40 mol / 284 K

• ΔS = 29.7 J/K