Question

In the diagram ABCD is a rectangle and PQ is parallel to AD
The area of ABCD is 60cm squared
The area of APQD is 24cm squared
calculate the value of f and g​

Answer 1

Answer:

f = 4

g = 6

Step-by-step explanation:

subtract areas to find the area of BCPQ:

60-24 = 36

Solve for g using area of BCPQ:

36=9f

f=4

since they rectangles are parallel use f to solve for g:

24=4g

g=6

Answer 2

The values of $f$ and $g$ are  $4cm$ and $6cm$ .

What is area ?

Area is the amount of space which is occupied by any 2D shape.

Area $=Length\ *\ Breadth$

We have,

$ABCD$ is a rectangle,

$PQ$ is parallel to $AD$,

And, $QC=9cm^2$

        $BC=QP=f\ cm$ and $DQ=g\ cm$,

The area of $ABCD$  $=60cm^2$ .

The area of $APQD$  $=24cm^2$

So,

Lets find the area of the remaining part i.e. $BCPQ$,

The area of  $BCPQ=$ The area of $ABCD-$ The area of $APQD$

                                 $=60-24$

The area of  $BCPQ$ $=36cm^2$

Now,

The area of  $BCPQ$ $=QC\ *\ BC$

                             $36=9\ *\ f$

⇒                           $f=4cm$

Now,

The area of $APQD$  $=24cm^2$

                         $g\ *\ f=24$

⇒                      $g\ *\ 4=24$

                               $g=6cm$

The values of $f$ and $g$ are $4$ and $6$ .

Hence, we can say that the values of $f$ and $g$ are  $4cm$ and $6cm$ .

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