Question

Claim: Fewer than 93​% of adults have a cell phone. In a reputable poll of 1021 ​adults, 88​% said that they have a cell phone. Find the value of the test statistic. The value of the test statistic is nothing. ​(Round to two decimal places as​ needed.)

Answer 1

Answer: -6.26

Step-by-step explanation:

Test statistic for population proportion is given by :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

, where p = population proportion.

$\hat{p}$ = sample proportion.

n= sample size.

As per given , we have

$H_a:p<0.93$

n= 1021

$\hat{p}=0.88$

Then, the test statistic will be :-

$z=\dfrac{0.88-0.93}{\sqrt{\dfrac{0.93(1-0.93)}{1021}}}\\\\=\dfrac{-0.05}{\sqrt{0.0000637610186092}}\\\\=\dfrac{-0.05}{0.0079850496936}\\\\=-6.26170179506\approx-6.26$

Hence, the value of the test statistic is -6.26 .

Answer 2

The value of the test statistic is mathematically given as

$z=-6.26170179$

What is the value of the test statistic?

Question Parameters:

Fewer than 93​% of adults have a cell phone

In a reputable poll of 1021 ​adults, 88​% said that they have a cell phone.

Generally, the equation for the Test statistic for a population proportion  is mathematically given as

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Therefore

$z=\dfrac{0.88-0.93}{\sqrt{\dfrac{0.93(1-0.93)}{1021}}}$

$z=-6.26170179$

In conclusion,  the value of the test statistic is

$z=-6.26170179$

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