Respuesta :
Answer:
F. Itz a trick queStion!!!!!!
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HOP I HLEPED!
Answer:
1/4
Explanation:
The trait is X-linked and recessive. A male only need one recessive allele to be affected while a female needs 2 recessive alleles to be affected.
Let the color vision allele be C.
Ginny is heterozygous, her genotype will be [tex]X^C X^c[/tex]
Harry is color blind, his genotype will be [tex]X^c Y[/tex]
If Ginny and Harry mate, their offspring's genotype will be: [tex]X^C X^c, X^C Y, X^c X^c, X^c Y[/tex]
[tex]X^C X^c[/tex] is a heterozygous female with normal vision
[tex]X^C Y[/tex] normal vision male
[tex]X^c X^c[/tex] color blind female
[tex]X^c Y[/tex] color blind male
Probability of having a color blind child = 1/2
Probability of having a son = 1/2
Probability of having a colorblind son = probability of having a colorblind child and probability of the child being a son
= 1/2 x 1/2
= 1/4
The probability of at least one of the children being a colorblind son is 1/4