Question

The speed in case a is twice that of case b. The circles radius in case a is two times that of case b. How does the acceleration in case a compare to the acceleration in case b?

Answer 1

Answer:

acceleration of a is twice the acceleration of b.

Explanation:

va = 2v

vb = v

ra = 2r

rb = r

Acceleration is given by

$A=\frac{v^{2}}{r}$

So, acceleration of a is given by

$A_{a}=\frac{4v^{2}}{2r}$....(1)

acceleration of b is given by

$A_{b}=\frac{v^{2}}{r}$.... (2)

dividing (1) by (2), we get

$\frac{A_{a}}{A_{b}}=2$

Thus, acceleration of a is twice the acceleration of b.