The current in the circuit is 5 A
Explanation:
The intensity of current is given by the equation:
[tex]I=\frac{q}{t}[/tex]
where
I is the current
q is the amount of charge passing through a given point of the circuit in a time interval of t
For the cell in this problem, we have
q = 150 C is the charge
t = 30 s is the time interval
Substituting into the equation, we f ind
[tex]I=\frac{150}{30}=5 A[/tex]
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