Question

The combined math and verbal scores for females taking the SAT-I test are normally distributed with a mean of 998 and a standard deviation of 202 (based on date from the College Board). If a college includes a minimum score of 1025 among its requirements, what percentage of females do not satisfy that requirement?

Answer 1

Answer: There is 64.8% of females do not satisfy that requirement.

Step-by-step explanation:

Since we have given that

Mean = 998

Standard deviation = 202

We need to find the percentage of females do not satisfy that requirement.

If a college includes a minimum score of 1025 among its requirements,

So, it becomes,

$P(X<1025)\\\\P(\dfrac{\bar{X}-\mu}{\sigma}<\dfrac{1025-998}{202})\\\\=P(Z<0.1336)\\\\=0.6480\\\\=64.8\%$

Hence, there is 64.8% of females do not satisfy that requirement.