Answer: The lower bound of confidence interval would be 0.116.
Step-by-step explanation:
Since we have given that
p = 13.2%= 0.132
n = 1105
At 90% confidence,
z = 1.645
So, Margin of error would be
[tex]z\sqrt{\dfrac{p(1-p)}{n}}\\\\=1.645\times \sqrt{\dfrac{0.132\times 0.868}{1152}}}\\\\=0.0164[/tex]
So, the lower bound of the confidence interval would be
[tex]p-\text{margin of error}\\\\=0.132-0.0164\\\\=0.116[/tex]
Hence, the lower bound of confidence interval would be 0.116.