Question

Tourists were on the hiking trip for three days. In the first day they walked 1/8 of the trail. On the second day they walked 4/7 of the remaining path. On the third day they walked 1/3 of the remaining trail and the last 8 km. How many km is the whole trail?

Answer 1

Answer:

32 km.

Step-by-step explanation:

Let us assume that the whole trail is x km.

So, on the first day the tourists walked $\frac{x}{8}$ km.

Then the remaining distance after first day is $(x - \frac{x}{8}) = \frac{7x}{8}$ km.

Now, on the second day the tourists walked $\frac{4}{7}$ of the remaining path i.e. $\frac{4}{7} \times \frac{7x}{8} = \frac{x}{2}$ km.

So, the remaining path to travel after 2nd day is $(\frac{7x}{8} - \frac{x}{2}) = \frac{3x}{8}$ km.

On the third day they walked $\frac{1}{3}$ of the remaining trail and last 8 km.

So, $(\frac{3x}{8} - \frac{3x}{8} \times \frac{1}{3}) = 8$

⇒ $\frac{x}{4} = 8$

⇒ x = 32 km. (Answer)