Respuesta :

ΔIJK ≈ ΔPQR => ∡I = ∡P =>

=> 3X + 4 = 72 - X

3X + X = 72 - 4

4X = 68

X = 68 : 4

X = 17

Answer:

since the triangles are congruent, and you're given the measures of [tex] \angle I \text{and} \angle P[/tex] which are "corresponding part of the congruent triangles" so they must be equal

hence,

[tex] m\angle I = m\angle P \\ \implies 3x+4=72-x \\ \implies 4x=68 \\ \implies x=17° [/tex]

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