how do you solve this step by step?

ΔIJK ≈ ΔPQR => ∡I = ∡P =>
=> 3X + 4 = 72 - X
3X + X = 72 - 4
4X = 68
X = 68 : 4
X = 17
Answer:
since the triangles are congruent, and you're given the measures of [tex] \angle I \text{and} \angle P[/tex] which are "corresponding part of the congruent triangles" so they must be equal
hence,
[tex] m\angle I = m\angle P \\ \implies 3x+4=72-x \\ \implies 4x=68 \\ \implies x=17° [/tex]