Question

Write the equation in standard form for the circle with center (4,0) passing through 4,(11/2).

Answer 1

Answer:

The standard equation of circle is  $(x-4)^2 + (y)^2  = (\frac{11}{2}) ^2$

Step-by-step explanation:

The given circle has Center  = (4,0)

Passing through (4,11/2)

The standard form of the Circle is given as:

$(x-h)^2 + (y-k)^2  = r^2$

Here, (h,k) is the center coordinates and r : radius of the given circle.

So, here according to the question:

(h,k) = (4,0)  , (x,y) = (4,11/2)

Putting the above value sin the equation of circle, determine the value of r:

$(4-4)^2 + (\frac{11}{2} -0)^2  = r^2\\\implies (\frac{11}{2}) ^2 = r^2\\\implies r = (\frac{11}{2})$

Hence, the standard equation of circle is  $(x-4)^2 + (y-0)^2  = (\frac{11}{2}) ^2$