Question

A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs ?10. 1m squared floor tiles costs ?3. Work out the total costs of tiles and paints

Answer 1

Answer:

$5202

Step-by-step explanation:

The total surface area of the cuboidal hall is:

2LB + 2BH + 2LH.

This will be: 2(40*3) + 2(3*15) + 2(40*15)

which will give : 1530m square.

The cost of 25msq of paint is 10

then the cost of 1530 will be 1530x10/25 = 612.

The cost of 1msq of tiles is 3

then the cost of 1530 will be 1530 x 3

= 4590.

Then the total cost will be =$5202

Answer 2

The combined total cost of tiles and paint exists $924.

How to estimate the total costs of tiles and paints?

We have been given that a community hall exists in the shape of a cuboid. The hall exists 40 m long 15 m high and 3 m wide.

The paint will be needed for 4 walls and ceiling.

Let us find the area of walls and ceiling.

Area of walls and ceiling

$= (2 * 40 * 15)+(2 * 3 * 15)+(40 * 3)$

$=1200+90+120$

$=1410$

Therefore, the area of walls and ceiling exists $1410$ square meters.

The cost for 10 liters of paint exists $10 and 10-liter paint covers 25 square meters.

The total painting cost

$=10 *\left(\frac{1410}{25}\right)$

$=10 * 56.4=564$

Therefore, the total painting cost exists $564.

Tiles will be needed for the floor.

Let us estimate the area of the floor.

Area of floor $=40 * 3$ square meters

$= 120$ square meters

Let 1 m squared floor tiles cost $3.

So, the total cost for tiles $=3 * 120=360$

Therefore, the cost of the total tile exists $360.

Now let us estimate the combined total cost of tiles and paint.

Combined total cost $= 564 + 360 = 924$.

Therefore, the combined total cost of tiles and paint exists $924.

To learn more about the combined total cost

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