Question

A raindrop has a mass of 5.4 × 10-7 kg and is falling near the surface of the earth. Calculate the magnitude of the gravitational force exerted (a) on the raindrop by the earth and (b) on the earth by the raindrop.

Answer 1

Answer

given,

mass of raindrop = 5.4 × 10⁻⁷ kg

acceleration due to gravity = 9.8 m/s²

a) magnitude of gravitational force on the rain drop

   Force on the rain drop = m g

   Force on the rain drop = 5.4 × 10⁻⁷ x  9.8

                                          = 5.292 x 10⁻⁶ N

Hence, force on raindrop by earth is equal to 5.292 x 10⁻⁶ N

b) by newtons third law

    Force by the earth on the raindrop will be opposite to the force by raindrop on earth.

Force on earth by raindrop = - 5.292 x 10⁻⁶ N

  negative sign represent that force is acting in the opposite direction.

     

Answer 2

The magnitude of the gravitational force exerted on the raindrop by the earth is 5.29 x 10⁻⁶ N.

The the magnitude of the gravitational force exerted on the earth by the raindrop is -5.29 x 10⁻⁶ N.

The given parameters;

• mass of the raindrop, m = 5.4 x 10⁻⁷ kg
• acceleration due to gravity, g = 9.8 m/s²

The magnitude of the gravitational force exerted on the raindrop by the earth is calculated by applying Newton's second law of motion as follows;

F = mg

F = (5.4 x 10⁻⁷)(9.8)

F = 5.29 x 10⁻⁶ N.

The the magnitude of the gravitational force exerted on the earth by the raindrop is calculated as;

$F_2 = -F\\\\F_2 = -5.29\times 10^{-6} \ N$

Learn more here:https://brainly.com/question/19887955