A 1.0kg ball is swinging in a horizontal circle on the end of a 1.5m long string that makes an angle O with the horizontaol. The string passes through a tube and has a 2.0kg block hanging from the ned of the string. Find the speed of the ball if the block is to remain stationary?

Respuesta :

Answer:

[tex]v = 4.7 m/s[/tex]

Explanation:

As we know that the ball is swinging in a circle

so here net horizontal centripetal force on the ball is due to component of the tension force

so we will have

[tex]T sin\theta = m\omega^2 r[/tex]

[tex]T cos\theta = mg[/tex]

also we know that

[tex]T = Mg[/tex]

so we have

[tex]Mg cos\theta = mg[/tex]

[tex]\theta = \frac{1}{2}[/tex]

[tex]\theta = 60 degree[/tex]

now we have

[tex]Mg sin\theta = m\omega^2 (Lsin\theta)[/tex]

[tex]Mg = m\omega^2 L[/tex]

[tex]2 \times 9.81 = 1 \omega^2 (1.5)[/tex]

[tex]\omega = 3.62 rad/s[/tex]

now we have

[tex]v = r\omega[/tex]

[tex]v = (1.5 sin60) (3.62)[/tex]

[tex]v = 4.7 m/s[/tex]

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