Question

World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15m/s^2 .
Part A
How much horizontal force F must a sprinter of mass 64 kg exert on the starting blocks to produce this acceleration?
Express your answer in newtons using two significant figures.
Part B
Which body exerts the force that propels the sprinter, the blocks or the sprinter?
Which body exerts the force that propels the sprinter, the blocks or the sprinter?
the blocks
the sprinter

Answer 1

Answer:

A)960N B) reaction force of the blocks

Explanation:

Force that the sprinter exacts on the block = mass of the sprinter * acceleration m/s^2 = 64 Kg * 15m/s^2 = 960N

B) It is the reaction force of the blocks that propels the sprinter using Newton's third law of motion that to very force there is an equal and opposite reaction force.

Answer 2

A) The horizontal force F should be 960N

B) The body exerts the force should be reaction force of the blocks

Calculation of the horizontal force:

A. Force that the sprinter exacts on the block = mass of the sprinter × acceleration m/s^2

= 64 Kg × 15m/s^2

= 960N

B) It is the reaction force of the blocks that propels the sprinter by applying  Newton's third law of motion.

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