Question

A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries three-fourths, three-halves, 3, 6, 12. Which exponential function is represented by the values in the table? f(x) = 3(2x) f(x) = 2(2x) f(x) = 3(3x) f(x) = 2(3x)

Answer 1

Answer:

$f(x) = 3(2)^{x}$

Step-by-step explanation:

A 2-column table has 5 rows.

The first column is labeled x with entries -2, -1, 0, 1, 2.

Now, the second column is labeled f(x) with entries 4/3, 3/2, 3, 6, 12.

Now, we are given four different exponential functions and we have to choose which one has those corresponding values.

Now, given f(0) = 3 and f(1) = 6

Therefore, the function $f(x) = 3(2)^{x}$ only satisfy the above given values in the table.

Hence, the function is $f(x) = 3(2)^{x}$ (Answer)

Answer 2

Answer:

option a

Step-by-step explanation: