Question

Consider this system of equations. Which shows the first equation written in slope-intercept form? 1/2(2y+10)=7x

A. y= 7x-10
B. y= 7/2x-5
C. y=7x-5
D. y=7/4x-5

Answer 1

Answer:

C) y=7x-5

Step-by-step explanation:

1/2(2y+10)=7x

y+5=7x

y=7x-5

Answer 2

Answer:  C. $y=7x-5$

Step-by-step explanation:

The equation of a line in slope intercept form is given by :-

$y=mx+c$

The given equation is $\dfrac{1}{2}(2y+10)=7x$

Multiplying 2 on both sides in the above equation , we get

$2y+10=14x$

Subtract 10 from both sides , we get

$2y=14x-10$

Divide both sides by 2 , we get

$y=7x-5$

Hence, the first equation written in slope-intercept form : $y=7x-5$