Answer:
butan-2-ol
Explanation:
The reaction is of an alkene with water in acidic medium. This will give addition product where water will add on the alkene according to Markovnikov's rule.
However, as alkene is symmetrical,w we will get single addition product.
The steps will be
a) There will be protonation of alkene with the acid (the catatlyst), resulting in formation of carbocation.
b) the carbocation formed will be attacked by water molecule, following by deprotonation to give alcohol.
The reaction is shown in the figure.
