Answer:
In the given parabola [tex]y=x^2+6x-9[/tex] the line of symmetry is the axis x = -3
Step-by-step explanation:
Here, the given equation of the parabola is : [tex]y=x^2+6x-9[/tex]
Now, in the Standard Form of the Parabolic Equation: [tex]y=ax^2+bx+c[/tex],
The axis of symmetry is a vertical line x = −b / 2 a .
Now, here comparing the given parabolic equation with teh standard form, we get :
a = 1 , b = 6 and c = -9
So, the axis of symmetry = [tex]-\frac{b}{2a} =- \frac{6}{2(1)} = -3[/tex]
Hence, here in the given parabola [tex]y=x^2+6x-9[/tex] the line of symmetry is the axis x = -3.