Respuesta :

Answer:

In the given parabola  [tex]y=x^2+6x-9[/tex]  the line of symmetry is the axis x  = -3

Step-by-step explanation:

Here, the given equation of the parabola is : [tex]y=x^2+6x-9[/tex]

Now, in the Standard Form of the Parabolic Equation: [tex]y=ax^2+bx+c[/tex],

The axis of symmetry is a vertical line x  = −b / 2 a .

Now, here comparing the given parabolic equation with teh standard form, we get  :  

a  = 1 , b = 6 and c  = -9

So, the axis of symmetry =  [tex]-\frac{b}{2a}  =- \frac{6}{2(1)} =  -3[/tex]

Hence, here in the given parabola  [tex]y=x^2+6x-9[/tex]  the line of symmetry is the axis x  = -3.

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