Answer: 0.08
Step-by-step explanation:
Given : The probability that the person is female : P(F)=80%=0.080
The probability that the females attended college : P(A|F)=90%=0.90
Then, the probability that the females do not attended college :
[tex]P(A^c|F)=1-P(A|F)=1-0.90=0.10[/tex]
Now using conditional probability formula :
[tex]P(M|N)=\dfrac{P(M\cap N)}{P(N)}[/tex]
We get,
[tex]P(A^c|F)=\dfrac{P(A^c\cap F)}{P(F)}[/tex]
Substitute the values , we get
[tex]0.10=\dfrac{P(A^c\cap F)}{0.80}\\\\\Rightarrow\ P(A^c\cap F)=0.80\times0.10=0.08[/tex]
Hence, the probability that the person selected is a female who did NOT attend college is 0.08 .