43.5 mL
We are given;
We are required to determine the volume of acid that must be used.
M1V1 = M2V2
Rearranging the formula;
V1 = M2V2 ÷ M1
= (1.74 M × 200 mL) ÷ 8 M
= 43.5 mL
Therefore, the volume of the concentrated acid that must be added is 43.5 mL