Respuesta :
Answer:
[tex]\$11,826.72[/tex]
Step-by-step explanation:
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
[tex]P=\$10,000\\n=12[/tex]
[tex]t=5\ years\ 3\ months=5+\frac{3}{12}=5.25\ years[/tex]
[tex]r=3\frac{1}{5}\%=(3+\frac{1}{5})\%=3.2\%=3.2/100=0.032[/tex]
substitute in the formula above
[tex]A=10,000(1+\frac{0.032}{12})^{12*5.25}[/tex]
[tex]A=10,000(\frac{12.032}{12})^{63}[/tex]
[tex]A=\$11,826.72[/tex]
Answer:
Actually, The top answer is wrong... The answer would be $1,826.72 ( Sorry...not trying to be rude or anything)
Step-by-step explanation: I know this because it's a gradpoint answer.
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