Answer:
W=972.83 J
Explanation:
Given,
angle of inclination of ramp = θ = 24.3°
Force exerted on the block = F= 289 N
Crate is raised to height of = 2.39 m
coefficient of friction = 0.33
where g is the acceleration due to gravity = g = 9.8 m/s²
Work done = ?
let m be the mass of the crate
Gravity force along ramp = m g sinθ
Friction force = μm g cosθ
now writing all the force
F = m g sinθ + μm g cosθ
By putting the values
F = m g (sinθ + μcosθ)
289 = 9.8 x m ( sin 24.3°+ 0.33 cos 24.3°) ( take g =10 m/s²)
289 = 9.8 m(0.71)
m = 41.53 kg
Work done will be equal to
W= m g h
W= 41.53 x 9.8 x 2.39 J
W=972.83 J
