Answer: 0.8031
Step-by-step explanation:
Binomial distribution:
For a binomial variable x,
The probability of getting success in x trials = [tex]P(X=x)=^nC_xp^x(1-p)^{n-x}[/tex]
, where n = Total trials .
p= Probability of getting success in each trial.
For the given situation , we take x as the number of damaged apple .
Given : The proportion of damaged apples : p=0.15
n= 10
Then, the probability that his sample will contain at least one damaged apple. :-
[tex]P(x\geq1)=1-P(x<1)\\\\=1-P(x=0)\\\\=1-^{10}C_{0}(0.15)^0(1-0.15)^{10}\\\\=1-(1)(0.85)^{10}\ \ [\because\ ^nC_0=1]\\=1-0.196874404341=0.803125595659\approx0.8031[/tex]
Hence, the required probability = 0.8031