Answer:
1.6 ×10⁻¹ kj
Explanation:
Given data:
Mass of chloroethane = 0.38 g
Heat absorbed = ?
Solution:
Molar mass of chloroethane = 64.51 g/mol
Molar heat of vaporization = 26.4 kj/mol
Number of moles:
Number of moles = mass/ molar mass
Number of moles = 0.38 g/ 64.51 g/mol
Number of moles = 0.006 mol
Heat absorbed:
0.006 mol × 26.4 kj/mol
0.16 kj
or 1.6 ×10⁻¹ kj
