Question

A fly undergoes a displacement of -5.80m while accelerating at -1.33m/s^2 for 4.22 s what was the initial velocity of the fly?

Answer 1

Answer:

1.43 m/s

Explanation:

From the question, we have;

• Displacement, s = -5.80 m
• Acceleration, a = - 1.33 m/s²
• Time, t is 4.22 s

We are required to calculate the initial velocity, u of the fly;

• We are going to use the suitable equation of linear motion.
• In this case, the suitable equation is;

S = 0.5at² + ut , where S is the displacement. a is the acceleration, u is the initial velocity and t is time

• Putting the values of the variables, we get;

-5.80 m = (0.5 × (-1.33 m/s²) × (4.22 s)²) + (u×4.22 s)

-5.80 m = -11.8426 + 4.22u

4.22u = 6.0426

      u  = 1.432 m/s

          = 1.43 m/s

Therefore, the initial velocity of the fly is 1.43 m/s