Answer:
[tex]x=0,x=-4,x=-3[/tex]
Step-by-step explanation:
The given equation is
[tex]x^3 + 7x^2 + 12x = 0[/tex]
Factoring by x:
[tex](x^2 + 7x + 12)x = 0[/tex]
One of the root is x=0. Let's solve the parentheses.
Expanding the trinomial
[tex]x^2 + 4x+3x + 12=0[/tex]
Factoring
[tex]x(x + 4)+3(x + 4)=0[/tex]
Factoring
[tex](x + 4)(x+3)=0[/tex]
This will give us the two remaining roots
[tex]x=-4,x=-3[/tex]