Question

A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32° ramp, measured from the horizontal, at a speed of 40.0 m/s (144 km/h). The top of the ramp is at the same height as the roofs of the buses and each bus is 20.0 m long.

Answer 1

Answer:

Dare devil can cross 7 buses.

Explanation:

given,                                        

angle of inclination of ramp = 32°

speed of the motorcycle = 40 m/s

length of bus = 20 m                                    

how many buses daredevil can clear =?                                

to solve this we need to calculate the range of the daredevil

considering it as projectile

the range of motorcyclist

     $R = \dfrac{V^2 sin (2\theta)}{g}$

     $R = \dfrac{40^2 sin (2\times 32^0)}{9.8}$

     $R =163.26 \times sin(2\times 32^0)$

     $R =146.74\ m$                    

length of bus is given as 20 m            

Number of bus daredevil can cross            

     $N = \dfrac{147.74}{20}$                

     $N =7.34$                                

Dare devil can cross 7 buses.

Answer 2

Answer:

The number of buses are 7.

Explanation:

Given that,

Angle =32°

Speed = 40.0 m/s

Length of bus = 20.0

We need to calculate the range of bus

Using formula of range

$R=\dfrac{v^2\sin2\theta}{g}$

Where, g = acceleration due to gravity

v = initial velocity

Put the value into the formula

$R=\dfrac{(40.0)^2\times\sin(2\times32)}{9.8}$

$R=150.20\ m$

We need to calculate the number of buses

Using formula of number of buses

$N=\dfrac{R}{L}$

Where, R = range

L = length of bus

$N=\dfrac{150.20}{20.0}$

$N=7$

Hence, The number of buses are 7.