Answer:
Speed of the water that emerge out of the pipe is 18.8 m/s
Explanation:
Since we know that water drops projected upwards to maximum height of 18 m
So here we can use kinematics equations here
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
here we have
[tex]v_f = 0[/tex]
[tex]d = 18 m[/tex]
[tex]a = -9.80 m/s^2[/tex]
so we will have
[tex]0 - v_i^2 = 2(-9.80)(18)[/tex]
[tex]v_i = 18.8 m/s[/tex]