2x-y=2--------------(i)
2x-2y=4------------(ii)
Multiplying eqn i by 2 and subtracting with ii
4x-2y=4
2x-2y=4
- + -
________
2x=0
X=0
Putting the value of x in i
2×0-y=2
-y=2
y=-2
Hence the value of x is 0 and y is -2
(2x - y = 2 => y = 2x - 2
(2x - 2y = 4
2x - 2(2x - 2) = 4
2x - 4x + 4 = 4
- 2x = 0
x = 0
y = 2·0 - 2
y = - 2
