The following chemical reaction will occur:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
Explanation:
Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.
The chemical reaction is:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
where:
(l) - liquid
(s) - solid
Learn more about:
balancing chemical equations
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