Answer:
2.27m/s
Explanation:
The coefficient of sliding friction = 0.38, the incline angle = 60o
Coefficient of sliding friction = frictional force/ force of normal (fn)
The normal force = mgcos60 where m is the mass of the body and g is acceleration due to gravity
Frictional force = coefficient of friction*fn = 0.38*9.81*m*cos 60 = 1.8639m
Force tending to push the body down the incline plane = mgsin60 = 8.496m
Net force on the body = force pushing downward - Frictional force
Net force = 8.496m - 1.8639m = 6.632m
Kinetic energy of the body = 1/2 mv^2 = work done by the net force pushing the body down = net force * distance travelled
1/2mv^2 = 6.632m * 0.387in meters
Cancel mass on both side leaves 1/2v^2 = 6.632*0.387
V^2 = 2.566584*2 = 5.133
V = √5.133 = 2.27m/s
