Question

Arrange the following molecules in order of increasing bond angles (smallest first): (A) XeF4.(B) CH4.(C) H2O.(D) BeH2. Enter four letters in order: (e.g. ABCD, DCBA, ACBD, etc.)"

Answer 1

Answer:

ACBD

Explanation:

The bond angles of the given molecules will be:

$XeF_{4}$

Square planar shape

Bond angle = 90°

$CH_{4}$ =

Tetrahedral

Bong angle = 109.5°

$H_{2}O$ =

Bent shape

Bong angle = 104.5°

$BeH_{2}$ =

Linear

Bong angle = 180°

Thus the order will be:

$XeF_{4}$ <$H_{2}O$<$CH_{4}$<$BeH_{2}$