Answer:
A) 5.1*10^10m B) 5.4*10^6m
Explanation:
Using the surface radiation formula of P (energy per second in Watt) = emissivity constant * surface area * Stefan-boltzmann constant*Temperature in kelvin^4*
2.7*10^31 = 1* 5.67*10^-8*A*11000^4
Making A subject of the formula = 2.7*10^31/ (5.67*10^-8*1.46*10^16) = 0.3261*10^23m^2
Since the shape is a sphere, the surface area = 4πR^2(radius of the Rigel)
R = √ (0.3261*10^23/ 4*π) = 5.1 * 10^ 10m
B) repeating the same step
2.1 *10^23 = 1*A*5.67*10^-8*10000^4 where A is the surface area of the Procyon
Make A subject of the formula
A = 2.1*10^23/(5.67*10^-8*10^16)
A = 0.37*10^15
The star assumed to be a sphere;
A = 4πR^2 where R is the radius of Procyon
R = √(0.37*10^15/4π) = 5.4*10^6m