Respuesta :
Answer:
heat absorbed by water = 2.39 KJ
Explanation:
given,
mass of molten NaCl = 5 g
mass of water = 25 g
Temperature of water = 25.0 °C
Temperature increased to = 47.9 °C
heat absorbed by water = m S ΔT
S is specific heat in J/gm °C
Specific heat of water = 4.184 J/gm °C
m is mass of water
heat absorbed by water = 25 x 4.184 x (47.9-25)
= 25 x 4.184 x 22.9
= 2395.34 J
heat absorbed by water = 2.39 KJ
The amount of heat transferred is 2.39 KJ.
What is Heat?
This is the form of energy which is transferred from one body to another as the result of a difference in temperature.
Parameters
mass of molten NaCl = 5 g
mass of water = 25 g
Temperature of water = 25.0 °C
Final Temperature of water = 47.9 °C
Specific heat of water = 4.184 J/gm °C
Heat = m S ΔT
Heat absorbed by water = 25 x 4.184 x (47.9 -25)
= 25 x 4.184 x 22.9 = 2395.34 J
= 2.39 KJ.
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