Answer:
0.6
Step-by-step explanation:
Given:
P( Person chosen at random has a B.S. degree), P(C) = 0.5
P( Person chosen at random does not have a B.S. degree), P(C') = 1 - 0.5 = 0.5
P(Student earns more than $100,000) = P(E)
P(Student earns more than $100,000, without going college) = P(E | C') = 0.4
P(Student earns more than $100,000, with college degree) = P(E | C) = 0.6
Now,
P(at least a B.S. degree | earns more than $100,000), P(C | E)
using Baye's theorem
we have
P(C | E) = [tex]\frac{P(C)\timesP(E | C)}{P(C)\timesP(E | C)+P(C')\timesP(E | C')}[/tex]
or
P(C | E) = [tex]\frac{0.5\times0.6}{0.5\times0.6+0.5\times0.4}[/tex]
or
P(C | E) = [tex]\frac{0.3}{0.5}[/tex]
or
P(C | E) = 0.6