Question

A discus thrower accelerates a discus from rest to a speed of 25.3 m/s by whirling it through 1.29 rev. Assume the discus moves on the arc of a circle 0.96 m in radius. A discus thrower moving in a circle as he prepares to throw the discus. (a) Calculate the final angular speed of the discus. rad/s

Answer 1

Answer:

ω = 26.35 rad/s

Explanation:

given,                            

speed of discus thrower = 25.3 m/s

whirling through  = 1.29 rev          

radius of circular arc = 0.96 m          

final angular speed of the discus = ?

using formula                      

v =  ω r                  

v  is the velocity of disk

ω is the angular speed of the discus

r is the radius of arc                      

$\omega = \dfrac{v}{r}$                

$\omega = \dfrac{25.3}{0.96}$                      

      ω = 26.35 rad/s

Final angular speed of the discus is equal to ω = 26.35 rad/s