Answer:
Consider the following calculations
Explanation:
Co = low fare = $ 100
Cu = high fare - low fare = 400 - 100 = $ 300
Critical ratio = Cu/(Cu+Co) = 300/(300+100) = 0.75
In the table, look for F(q) >= 0.75 , that value is 0.792 and corresponding value of q = 12. Therefore,
Optimal protection level = 12
Refer the table for q=12, Expected shortage, L(q) = 0.5
Expected high fare seats to be sold = Mean demand - Expected shortage = 10-0.5 = 9.5
Probability of a full flight = 0.792